Q. In the reaction of (S) 2-phenylpropamide with $NaBr/H_{2}O$ to give 1-phenylethylamine
A) There is retention of configuration
B) There is inversion of configuration
C) A mixture of two products is obtained
D) There is no reaction
Explanation
(a)
Hofmann bromamide degradation takes place with complete retention of stereochemical configuration in the migrating alkyl group
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.