Explanation

(d)
Benzyl amine $\left( C_{6}H_{5}CH_{2}NH_{2} \right)$ is more basic than aniline $\left( C_{6}H_{5}NH_{2} \right)$ because N-atom of aniline is delocalized over the benzene ring. However in benzyl amine the lone pair of electrons on the N-atom is not conjugated with the benzene ring and therefore it is not delocalized. Hence, the lone pair of electrons on the N-atom in benzyl amine is more readily available for protonation than that on the N-atom of aniline. Thus, the benzyl amine is a stronger base than aniline.