Q. A compound of molecular formula $C_{3}H_{9}N\$when reacts with benzene sulphonyl chloride gives a product soluble in dilute NaOH solution. The compound should be
A) $\left( CH_{3} \right)_{3}N$
B) $\left( CH_{3} \right)_{2}CH - NH_{2}$
C) [image:13_image160.emf]
D) All of these
Explanation
The correct answer is Option B: $\left( CH_{3} \right)_{2}CH - NH_{2}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.