Q.
The alkene formed as a major product in the above elimination reaction is
A) [image:13_image177.emf]
B) $CH_{2} = CH_{2}$
C) [image:13_image178.emf]
D) [image:13_image179.emf]
Explanation
(b)
[image:13_image237.emf]
There are four $\beta$- hydrogens, in this quaternary ammonium salt.
On heating quaternary ammonium salt gives Hofmann elimination (abstraction of most acidic hydrogen which is $\beta^{1}$).
Hence, major product is $CH_{2} = CH_{2}$. (Least substituted alkene).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.