$CH_{3}CONH_{2}.{Br}_{2}$ and KOH give $CH_{3}NH_{2}$ as the product. The intermediates of the reaction are (A) [image:13_image180.emf] B) $CH_{3} - N = C = O$ (C)C$H_{3}NHBr$ (D) $CH_{3}CONBr_{2}$ The correct answer is

Question

Dr. Abubacker · Accepted Answer

The correct answer is Option A: A, B.

Q. $CH_{3}CONH_{2}.{Br}_{2}$ and KOH give $CH_{3}NH_{2}$ as the product. The intermediates of the reaction are (A)

B) $CH_{3} - N = C = O$ (C)C$H_{3}NHBr$ (D) $CH_{3}CONBr_{2}$ The correct answer is

Explanation

Reviewed by Dr. Abubacker

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Q. $CH_{3}CONH_{2}.{Br}_{2}$ and KOH give $CH_{3}NH_{2}$ as the product. The intermediates of the reaction are (A) B) $CH_{3} - N = C = O$ (C)C$H_{3}NHBr$ (D) $CH_{3}CONBr_{2}$ The correct answer is

Explanation

Reviewed by Dr. Abubacker

Want more practice?

Q. $CH_{3}CONH_{2}.{Br}_{2}$ and KOH give $CH_{3}NH_{2}$ as the product. The intermediates of the reaction are (A)

B) $CH_{3} - N = C = O$ (C)C$H_{3}NHBr$ (D) $CH_{3}CONBr_{2}$ The correct answer is