Q. Given the polymers, A = Nylon 6.6; B=Buna –S;C= Polythene. Arrange these in increasing order of their intermolecular force (lower to higher).
A) $A < B < C$
B) $A < C < B$
C) $B < C < A$
D) $B < C < B$
Explanation
(c)
Buna-S is a elastomer, thus has weakest intermolecular forces. Nylon 66, is a fibre, thus has strong intermolecular forces like H-bonding. Polythene is a thermoplastic polymers,thus the intermolecular force present in polythene are in between elastomer and fibres. Thus, the order of intermolecular force of these polymers is
$Buna - S\ < Polythene\ < Nylon\ 66$
$(B)(C)(A)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.