Q. Catalyst used in dimerisation of acetylene to ‘prepare’ chloroprene is
A) ${HgSO}_{4} + H_{2}{SO}_{4}$
B) ${Cu}_{2}{Cl}_{2}$
C) ${Cu}_{2}{Cl}_{2} + {NH}_{4}Cl$
D) ${Cu}_{2}{Cl}_{2} + {NH}_{4}OH$
Explanation
(c)
$2HC = CH\ \underset{NH_{4}Cl}{\overset{\ \ \ \ \ Cu_{2}Cl_{2}}{\rightarrow}}H_{2}C = CH - C = CH$
vinyl acetylene
$\overset{\ \ \ HCl\ \ \ }{\rightarrow}\ CH_{2} = CH - C = CH_{2}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \ \$
$Cl$
Chloroprene
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.