(d) $\because\ \ \ \ \ \ \ \ \ \ \ \ n(A \times B \times C) = n(A) \times n(B) \times n(C)$ $\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ n(C) = \frac{24}{4 \times 3} = 2$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.