If sets $A$ and $B$ are defined as $A = \left\{ (x,\ y):y = \frac{1}{x},0
eq x \in R ight\}$, $B = \left\{ (x,\ y):y = - x,\ x \in R ight\}$, then

Question

If sets $A$ and $B$ are defined as $A = \left\{ (x,\ y):y = \frac{1}{x},0 
eq x \in R ight\}$, $B = \left\{ (x,\ y):y = - x,\ x \in R ight\}$, then

Dr. Abubacker · Accepted Answer

(c)
The set $A$ is the set of all points on the hyperbola $xy = 1$ having its two branches in the first and third quadrants, while the set $B$ is the set of all points on $y = - x$ which lies in second and four quadrants. These two curves do not intersect.
Hence, $A \cap B = \phi.$

Q. If sets $A$ and $B$ are defined as $A = \left\{ (x,\ y):y = \frac{1}{x},0 \neq x \in R \right\}$, $B = \left\{ (x,\ y):y = - x,\ x \in R \right\}$, then

Explanation

Reviewed by Dr. Abubacker

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