Q. If $f:R \rightarrow C$ is defined by $f(x) = e^{2ix}$ for $x \in R$, then $f$ is (where $C$ denotes the set of all complex numbers)

A) One-one
B) Onto
C) One-one and onto
D) Neither one-one nor onto
Explanation

(d)
Given, $f(x) = e^{2ix}$ and $f:R \rightarrow C$. Function $f(x)$ is not one-one, because after some values of $x(ie,\ \pi)$ it will give the same values.
Also, $f(x)$ is not onto, because it has minimum and maximum values $- 1 - i$ and $1 + i$ respectively.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.