Q. $f(x) = x + \sqrt{x^{2}}$ is a function from $R\ toR$, then $f(x)$ is
A) Injective
B) Surjective
C) Bijective
D) None of these
Explanation
(d)
Given, $f(x) = x + \sqrt{x^{2}}$
Since, this function is not defined
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.