(a) Let $y = f(x) = x^{3}$ $\therefore\ \ \ \ \ \ \ \ \ x = y^{1/3}$ $\Rightarrow \ \ \ \ \ \ \ \ f^{- 1}(x) = x^{1/3}$ $\therefore\ \ \ \ \ \ f^{- 1}(8) = (8)^{1/3} = 2$
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