Q. If $f(2x + 3) = \sin{x + 2^{x}},\$ then $f(4m - 2n + 3)$ is equal to
A) $\sin(m - 2m) + 2^{2m - n}$
B) $\sin{(2m - n) + 2^{(m - n)2}}$
C) $\sin{(m - 2n) + 2^{(m + n)2}}$
D) $\sin{(2m - n) + 2^{2m - n}}$
Explanation
(d)
Given, $f(2x + 3) = \sin{x + 2^{x}}$
Put $x = 2m - n$
$\therefore f\left\lbrack 2(2m - n) + 3 \right\rbrack = \sin{(2m - n) + 2^{2m - n}}$
$\Rightarrow \ \ \ \ \ \ \ f(4m - 2n + 3) = \sin{(2m - n) + 2^{2m - n}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.