(a) For $f(x)$ to be defined $\ \ \ \ \ \ \ \ \ \ \ \frac{5x - x^{2}}{4} \geq 1 \Rightarrow x^{2} - 5x + 4 \leq 0$ $\Rightarrow (x - 4)(x - 1) \leq 0\ \therefore x \in \lbrack 1,\ 4\rbrack$
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