Q.
Let $n(A) = 4$ and $n(B) = 6$. The number of one to one functions from $A$ to $B$ is
A) 24
B) 60
C) 120
D) 360
Explanation
(d)
Given, $n(A) = 4$ and $n(B) = 6$
Here, $n(B) > n(A)$
Since, the function $f$ is one-one and onto.
$\therefore$ Required number of ways
${= \ }^{6}P_{4} = \frac{6!}{2!} = 360$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.