Q. Range of the function $f(x) = \frac{x^{2} + x + 2}{x^{2} + x + 1};x \in R$ is

A) $(1,\ \infty)$
B) (1, 11/7)
C) [1, 7/3]
D) (1, 7/5)
Explanation

(c)
Let $y = \frac{x^{2} + x + 2}{x^{2} + x + 1}$
$\Rightarrow x^{2}(y - 1) + x(y - 1) + (y - 2) = 0,\ \forall\ x \in R$
Now, $D \geq 0\ \Rightarrow (y - 1)^{2} - 4(y - 1)(y - 2) \geq 0$
$\Rightarrow \ \ (y - 1)\{(y - 1) - 4(y - 2)\} \geq 0$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (y - 1)( - 3y + 7) \geq 0$
[image:2_image7.emf]
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \leq y \leq \frac{7}{3}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.