Q. Let $R = \{(1,\ 3),\ (4,\ 2),\ (2,\ 4),\ (2,\ 3),\ (3,\ 1)\}$ be a relation on the set $A = \{ 1,\ 2,\ 3,\ 4\}$. The relation $R$ is

A) A function
B) Transitive
C) Not symmetric
D) Reflexive
Explanation

(c)
$R = \left\{ (1,\ 3),\ (4,\ 2),\ (2,\ 4),\ (2,\ 3),\ (3,\ 1) \right\}$ is a relation on
$A = \left\{ 1,\ 2,\ 3,\ 4 \right\},$ then
(a) since, $(2,\ 4) \in R$ and $(2,\ 3) \in R$, so $R$ is not a function.
(b) since, $(1,3) \in R$ and $(3,\ 1) \in R$ but $(1,\ 1) \notin R$.
So, $R$ is not transitive.
(c) since, $(2,\ 3) \in R$ but $(3,\ 2) \notin R$, so $R$ is not symmetric.
(d) since, $(4,\ 4) \notin R$, so $R$ is not reflexive.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.