Q. The range of the function $f(x) = x^{2} - 6x + 7$ is
A) $( - \infty,\ 0)$
B) $\lbrack - 2,\ \infty)$
C) $( - \infty,\ \infty)$
D) $( - \infty,\ - 2)$
Explanation
(b)
$x^{2} - 6x + 7 = (x - 3)^{2} - 2$
Obviously, minimum value is $- 2$ and maximum is $\infty$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.