Q. The period of the function $f(\theta) = 4 + 4\sin^{3}{\theta - 3\sin\theta}$ is
A) $\frac{2\pi}{3}$
B) $\frac{\pi}{3}$
C) $\frac{\pi}{2}$
D) $\pi$
Explanation
(a)
Given
$f(\theta) = 4 + 4\sin^{3}{\theta - 3\sin\theta}$
$\ \ \ \ \ \ \ \ \ \ = 4 - \left( 3\sin{\theta - 4\sin^{3}\theta} \right) = 4 - \sin{3\theta}$
$\therefore$ Period of $f(\theta) = \frac{2\pi}{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.