If the function $f:R \rightarrow R$ defined by $f(x) = \lbrack x\rbrack$ where $\lbrack x\rbrack$ is the greatest integer not exceeding $x$, for $x \in R$, then $f$ is

Question

Dr. Abubacker · Accepted Answer

(c)
For even $f( - x) = f(x)$ and for odd, $f( - x) = - f(x)$
And $f(x)$ is increasing, if $f^{'}(x) > 0$.
Here, $f(x)$ is not differentiable at $x \in I$ and above two cases are also not satisfied by $f(x)$.
$	herefore\ \ f(x) = \lbrack xbrack$ is neither even nor odd.

Q. If the function $f:R \rightarrow R$ defined by $f(x) = \lbrack x\rbrack$ where $\lbrack x\rbrack$ is the greatest integer not exceeding $x$, for $x \in R$, then $f$ is

Explanation

Reviewed by Dr. Abubacker

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