Q. The domain of the function $f(x) = \frac{\sin^{1}{(x - 3)}}{\sqrt{9 - x^{2}}}$ is
A) [2, 3]
B) [2, 3)
C) [1, 2]
D) [1, 2)
Explanation
(b)
The function $f(x)$ will be defined, if
$\ \ \ \ - 1 \leq (x - 3) \leq 1 \Rightarrow \ 2 \leq x \leq 4$
And $9 - x^{2} > 0\ \Rightarrow \ - 3 < x < 3$
$\therefore\ \ \ 2 \leq x < 3$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.