(b)
Given, $f(x) = x - \lbrack x\rbrack,\ g(x) = \lbrack x\rbrack$ for $x \in R$.
$\therefore\ \ \ \ \ f\left( g(x) \right) = f(\lbrack x\rbrack)$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \lbrack x\rbrack - \lbrack x\rbrack$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 0$