$A = \left\{ 1,\ 2,\ 3,\ 4 \right\},\ B\left\{ 1,\ 2,\ 3,\ 4,\ 5,\ 6 \right\}$are two sets, and function $f:A \rightarrow B$ is defined by $f(x) = x + 2\ \forall x \in A$, then the function $f$ is

Question

Dr. Abubacker · Accepted Answer

(c)
$f(1) = 3,\ f(2) = 4,\ f(3) = 5,\ f(4) = 6$
$\Rightarrow 1 \in B,\ 2 \in B$ do not have any pre-image in $A$
$\Rightarrow f$ is one-one and into

Q. $A = \left\{ 1,\ 2,\ 3,\ 4 \right\},\ B\left\{ 1,\ 2,\ 3,\ 4,\ 5,\ 6 \right\}$are two sets, and function $f:A \rightarrow B$ is defined by $f(x) = x + 2\ \forall x \in A$, then the function $f$ is

Explanation

Reviewed by Dr. Abubacker

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