Q. The domain of the real valued function $f(x) = \sqrt{5 - 4x - x^{2}} + x^{2}log(x + 4)$ is
A) $- 5 \leq x \leq 1$
B) $- 5 \leq x$ and $x \geq 1$
C) $- 4 < x \leq 1$
D) $\phi$
Explanation
(c)
For $f(x)$ to be defined, $5 - 4x - x^{2} \geq 0$ and $x + 4 > 0$
$\Rightarrow \ - 5 \leq x \leq 1$
And $x > - 4$
$\Rightarrow \ \ - 4 < x \leq 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.