(b)
Since, $\left\lbrack b(x + 1)^{2} + c(x + 1) + d \right\rbrack - \left\lbrack bx^{2} + cx + d \right\rbrack - 8x + 3$
$\Rightarrow \ \ \ \ \ \ \ (2b)x + (b + c) = 8x + 3$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ 2b = 8,\ b + c = 3\ \Rightarrow b = 4,\ c = - 1$