(b) Let $y = \sqrt{\sin{2x}} \Rightarrow 0 \leq \sin{2x \leq 1}$, $\Rightarrow \ \ \ 0 \leq 2x \leq \frac{\pi}{2}$ $\Rightarrow \ \ \ 0 \leq x \leq \frac{\pi}{4}$ $\Rightarrow \ \ x \in \left\lbrack n\pi,\ n\pi + \frac{\pi}{4} \right\rbrack$
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Ph.D. in Physics with 19+ years of teaching experience.