The equation $\sin{x + siny + \sin{z = - 3}}$ for $0 \leq x \leq 2\pi,\ 0 \leq y \leq 2\pi,\ 0 \leq z \leq 2\pi$ has

Question

Dr. Abubacker · Accepted Answer

(a)
Given, $\sin{x + \sin{y + \sin{z = - 3}}}$ and $x,\ y,\ z\  \in \lbrack 0,\ 2\pibrack$
$\because$ The minimum value of sin is $- 1$
$	herefore$ In between 0 to $2\pi$, the given equation is satisfied at $x = \frac{3\pi}{2}$
$y = \frac{3\pi}{2},\ z = \frac{3\pi}{2}$ and having only one solution

Q. The equation $\sin{x + siny + \sin{z = - 3}}$ for $0 \leq x \leq 2\pi,\ 0 \leq y \leq 2\pi,\ 0 \leq z \leq 2\pi$ has

Explanation

Reviewed by Dr. Abubacker

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