(d)
$\tan{45{^\circ} = \frac{\tan{10{^\circ} + \tan{35{^\circ}}}}{1 - \tan{10{^\circ}\tan{35{^\circ}}}}}$
$\Rightarrow \ \ 1 - \tan{10{^\circ}\tan{35{^\circ} = \tan{10{^\circ} + \tan 35}}}{^\circ}$
$\Rightarrow \ \tan{10{^\circ} + \tan{35{^\circ} + \tan{10{^\circ}\tan{35{^\circ} = 1}}}}$