Q. The value of $\frac{\sin{55{^\circ} - \cos{55{^\circ}}}}{\sin{10{^\circ}}}$ is
A) $\frac{1}{\sqrt{2}}$
B) 2
C) 1
D) $\sqrt{2}$
Explanation
(d)
$\frac{\sin{55{^\circ} - \cos{55{^\circ}}}}{\sin{10{^\circ}}} = \frac{\sin{55{^\circ} - \sin{35{^\circ}}}}{\sin{10{^\circ}}} = \frac{2\cos{45{^\circ}.\sin{10{^\circ}}}}{\sin{10{^\circ}}}$
$= \sqrt{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.