Q. ${sech}^{- 1}\left( \frac{1}{2} \right)$ is
A) $\log{(\sqrt{3} + \sqrt{2})}$
B) $\log{(\sqrt{3} + 1)}$
C) $\log{(2 + \sqrt{3})}$
D) None of above
Explanation
(c)
${sech}^{- 1}\left( \frac{1}{2} \right) = \cosh^{- 1}(2)$
$= \log{\left( 2 + \sqrt{2^{2} - 1} \right) = \log{(2 + \sqrt{3})}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.