Explanation

(d)
$\sin{x = \frac{1}{2}}$
$\Rightarrow \ \sin{x = \sin\frac{\pi}{6}}$
$\Rightarrow x = n\pi + ( - 1)^{n}\frac{\pi}{6}$
For $- 2\pi \leq x \leq 2\pi$
$x = \frac{\pi}{6},\frac{5\pi}{6},\ - \frac{7\pi}{6},\ - \frac{11\pi}{6}$
$\therefore$ Number of points of intersection of two given curves$= 4$
Alternate
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The number of points of intersection are 4