(c)
We have, $(5 + 4\cos{\theta)(2\cos{\theta + 1) = 0}}$
$\Rightarrow \cos{\theta = - \frac{5}{4}}$ which is not possible
$\therefore\ 2\cos{\theta + 1 = 0\ \Rightarrow \ \ }\cos{\theta = - \frac{1}{2}}$
$\Rightarrow \ \theta = \frac{2\pi}{3},\frac{4\pi}{3}$
$\therefore$ Solution set is $\left\{ \frac{2\pi}{3},\frac{4\pi}{3} \right\} \in \lbrack 0,\ 2\pi\rbrack$