Q. In $\mathrm{\Delta}ABC$, if $\sin^{2}{A + \sin^{2}{B + \sin^{2}{C = 2}}}$, then the triangle is

A) Right angled, but need not be isosceles
B) Right angled and isosceles
C) Isosceles, but need not be right angled
D) Equilateral
Explanation

(a)
Given, $\sin^{2}{A + \sin^{2}{B + \sin^{2}{C = 2}}}$
$\Rightarrow \ \ 1 - \cos^{2}{A + 1 - \cos^{2}{B + 1 - \cos^{2}{C = 2}}}$
$\Rightarrow \ \ 1 = \cos^{2}{A + \cos^{2}{B + \cos^{2}C}}$
$\Rightarrow \ \ 1 = 1 - 2\cos{A\cos{B\cos C}}$
$\Rightarrow \ \cos{Acos\ B\cos{C = 0}}$
At least one should be $90{^\circ}$ and sum of two angles should be $90{^\circ}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.