Q. The general solution of $\sin^{2}{\theta\sec{\theta + \sqrt{3}\tan{\theta = 0}}}$ is
A) $\theta = n\pi + ( - 1)^{n + 1}\frac{\pi}{3},\ \theta = n\pi,\ n \in I$
B) $\theta = n\pi,\ n \in I$
C) $\theta = n\pi + ( - 1)^{n + 1}\frac{\pi}{3},n \in I$
D) $\theta = \frac{n\pi}{2},\ n \in I$
Explanation
(b)
The given equation can be rewritten as
$\tan{\theta(\sin{\theta + \sqrt{3}) = 0}}$
$\Rightarrow \tan{\theta = 0,}$ but $\sin{\theta + \sqrt{3}} \neq 0$
$\Rightarrow \tan{\theta = 0} \Rightarrow \ \theta = n\pi,\ n \in I$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.