Q. The most general value of $\theta$ which satisfy both the equations $\cos{\theta = - \frac{1}{\sqrt{2}}}$ and $\tan{\theta = 1}$, is
A) $2n\pi + \frac{5\pi}{4},\ n \in I$
B) $2n\pi + \frac{\pi}{4},\ n \in I$
C) $2n\pi + \frac{3\pi}{4},\ n \in I$
D) None of these
Explanation
(a)
Since, $\cos\theta$ is negative and $\tan\theta$ is positive which lies in IIIrd quadrant
$\therefore\ \ \ \ \theta = \frac{5\pi}{4}$ satisfies
Hence, general value of $\theta$ is $2n\pi + \frac{5\pi}{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.