Q. If $x\sin^{3}{\theta + y\cos^{3}{\theta = \sin{\theta\cos\theta}}}$ and $x\sin{\theta = y\cos\theta}$, then $x^{2} + y^{2}$ is

A) 2
B) 0
C) 3
D) 1
Explanation

(d)
Given, $x\sin^{3}{\theta + ycos^{3}\theta = \sin{\theta\cos\theta}}$
$\Rightarrow \ \ \ y\cos{\theta\sin^{2}{\theta + y\ cos^{3}\theta}} = \sin{\theta\cos\theta}$
$\lbrack\because\ \ x\sin{\theta = y\cos\theta}\rbrack$
$\Rightarrow \ \ y\cos{\theta\ \left( \sin^{2}{\theta + \cos^{2}\theta} \right) = \sin{\theta\cos\theta}}$
$\Rightarrow \ \ y = \sin\theta$
Now, $x\sin{\theta = \sin{\theta\cos{\theta\ \ \Rightarrow \ \ x = \cos\theta}}}$
$\therefore\ \ \ x^{2} + y^{2} = \cos^{2}{\theta + \sin^{2}{\theta = 1}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.