Q. $\mathrm{\Delta}\ ABC$ is right angled at $C$, then $\tan{A + \tan B}$ is equal to
A) $\frac{b^{2}}{ac}$
B) $a + b$
C) $\frac{a^{2}}{bc}$
D) $\frac{c^{2}}{ab}$
Explanation
(d)
$\tan{A = \frac{a}{b}},\tan{B = \frac{b}{a}}$
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$\therefore\ \tan{A + \tan{B = \frac{a^{2} + b^{2}}{ab}}}$
Since, $a^{2} + b^{2} = c^{2}$
$\therefore\ \tan{A + \tan{B = \frac{c^{2}}{ab}}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.