Explanation

(b)
(a)$\sin{\theta = \frac{5}{3}}$ is not possible, because the value of $\sin{\theta\ lies\ in\ \lbrack - 1,1\rbrack}$
(b)$\tan{\theta = 100^{2}}$. This is possible
(c)$\cos{= \ \frac{1 + p^{2}}{1 - p^{2}}},\ \lbrack p \neq \pm 1\rbrack\$this is not possible, because here, $\cos\theta$ is greater than one
(d)$\sec{\theta = \frac{1}{2},\ }$ this is not possible because $\sec\theta$ is not less than one
$\therefore\$Option (b) is true