Q. If $y = \cos^{2}{x + \sec^{2}x}$, then

A) $y \leq 2$
B) $y \leq 1$
C) $y \geq 2$
D) $1 < y < 2$
Explanation

(c)
We have, $y = \cos^{2}{x + \sec^{2}x}$
$\Rightarrow \ \ y = \left( \cos{x - \sec x} \right)^{2} + 2 \geq 2$
$\Rightarrow \ \ y \geq 2$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.