(c) Given, $\cos{5\theta = 0}$ $\Rightarrow 5\theta = \frac{\pi}{2} \Rightarrow \theta = \frac{\pi}{10}$ $\therefore\cos{\theta = \cos{\left( \frac{\pi}{10} \right) = \sqrt{\frac{10 + 2\sqrt{5}}{16}}}}$ $= \sqrt{\frac{5 + \sqrt{5}}{8}}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.