(b) $\frac{\cot{54{^\circ}}}{\tan{36{^\circ}}} + \frac{\tan{20{^\circ}}}{\cot{70{^\circ}}}$ $= \frac{\tan{36{^\circ}}}{\tan{36{^\circ}}} + \frac{\tan{20{^\circ}}}{\tan{20{^\circ}}}$ $= 1 + 1 = 2$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.