Q. The number of solutions of the pair of equations $2\sin^{2}{\theta - \cos{2\theta = 0}}$ and $2\cos^{2}{\theta - 3\sin{\theta = 0}}$ in the interval $\lbrack 0,\ 2\pi\rbrack$ is

A) Zero
B) One
C) Two
D) Four
Explanation

(c)
$2\sin^{2}{\theta - \cos{2\theta = 0\ \ \Rightarrow \ \sin^{2}{\theta = \frac{1}{4}\ \ \ \Rightarrow \ \sin{\theta = \pm \frac{1}{2}}}}}$ …(i)
Also, $2\cos^{2}{\theta = 3\sin{\theta\ \ \Rightarrow \ 2\sin^{2}{\theta + 3\sin{\theta - 2 = 0}}}}$
$\Rightarrow \ \ \sin{\theta = \frac{1}{2}}$ …(ii)
From Eqs. (i) and (ii), $\sin{\theta = \frac{1}{2}}$
Two solutions exist in $\lbrack 0,\ 2\pi\rbrack$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.