If $\sin^{2}{ heta = \frac{x^{2} + y^{2} + 1}{2x}}$, then $x$ must be

Question

If $\sin^{2}{	heta = \frac{x^{2} + y^{2} + 1}{2x}}$, then $x$ must be

Dr. Abubacker · Accepted Answer

(d)
Since, $\sin^{2}{	heta \leq 1}$
$\Rightarrow \ \ \frac{x^{2} + y^{2} + 1}{2x} \leq 0$
$\Rightarrow \ \ (x - 1)^{2} + y^{2} \leq 0$
Which is possible only when $x = 1,\ y = 0$
Hence, it also depends on value of $y$.

Q. If $\sin^{2}{\theta = \frac{x^{2} + y^{2} + 1}{2x}}$, then $x$ must be

Explanation

Reviewed by Dr. Abubacker

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