Q. The equation $\sin{x + \sin{y + \sin{\mathcal{z} = - 3\ for\ 0 \leq x \leq 2\pi,\ 0 \leq y \leq 2\pi,\ 0 \leq \mathcal{z} \leq 2\pi}}}$ has

A) One solution
B) Two sets of solutions
C) Four sets of solutions
D) No solution
Explanation

(a)
Given equation, $\sin{x + \sin{y + \sin{\mathcal{z} = - 3\ }}}$is satisfied only when $x = y = \mathcal{z =}\frac{3\pi}{2}$ for $x,\ y,\mathcal{z \in}\lbrack 0,\ 2\pi\rbrack$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.