Q. The expression $\tan^{2}{\alpha + \cot^{2}\alpha}$ is
A) $\geq 2$
B) $\leq 2$
C) $\geq - 2$
D) None of these
Explanation
(a)
$\because\ \ \ \left( \tan{\alpha - \cot\alpha} \right)^{2} \geq 0$
$\Rightarrow \ \tan^{2}{\alpha + \cot^{2}{\alpha - 2 \geq 0}}$
$\Rightarrow \ \tan^{2}{\alpha + \cot^{2}{\alpha \geq 2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.