Q. If $\sin^{2}{\theta = \frac{1}{4}}$ , then the most general value of $\theta$ is
A) $2n\pi \pm ( - 1)^{n}\frac{\pi}{6}$
B) $\frac{n\pi}{2} \pm ( - 1)^{n}\frac{\pi}{6}$
C) $n\pi \pm \frac{\pi}{6}$
D) $2n\pi \pm \frac{\pi}{6}$
Explanation
(c)
Since, $\sin^{2}{\frac{1}{4}\ \Rightarrow \sin^{2}{\theta = \sin^{2}\frac{\pi}{6}}}$
$\Rightarrow \ \theta = n\pi \pm \frac{\pi}{6}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.