Q. $\frac{\tan{80{^\circ} - \tan{10{^\circ}}}}{\tan{70{^\circ}}}$ is equal to
A) 0
B) 1
C) 2
D) 3
Explanation
(c)
$\frac{\tan{80{^\circ} - \tan{10{^\circ}}}}{\tan{(80{^\circ} - 10{^\circ})}}$
$= \frac{\tan{80{^\circ} - \tan{10{^\circ}}}}{\tan{80{^\circ} - \tan{10{^\circ}}}} \times (1 + \tan{80{^\circ}\tan{10{^\circ}}})$
$= 1 + \tan{80{^\circ}\tan{10{^\circ} = 2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.