Q. If$\ \tan{\beta = \cot{\theta\tan{\alpha,\ then\cot^{2}{\left( \frac{\theta}{2} \right)\ }}}}$is equal to
A) $\frac{\sin{(\alpha + \beta)}}{\sin{(\alpha - \beta)}}$
B) $\frac{\sin{(\alpha - \beta)}}{\sin{(\alpha + \beta)}}$
C) $\frac{\cos{(\alpha + \beta)}}{\cos{(\alpha - \beta)}}$
D) $\frac{\cos{(\alpha - \beta)}}{\cos{(\alpha + \beta)}}$
Explanation
The correct answer is Option A: $\frac{\sin{(\alpha + \beta)}}{\sin{(\alpha - \beta)}}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.