If $\sin{ heta = \sin{15{^\circ}}}$+sin 45${^\circ}$ ,where $0{^\circ}

Question

If $\sin{	heta = \sin{15{^\circ}}}$+sin 45${^\circ}$ ,where $0{^\circ} < 	heta < 90{^\circ}$, then $	heta$ is equal to0

Dr. Abubacker · Accepted Answer

(d)
$\sin{	heta = \sin{15{^\circ} + \sin{45{^\circ}}}}$
$= 2\sin{30{^\circ}\cos{15{^\circ} = 2 	imes \frac{1}{2} 	imes \cos{(90{^\circ} - 75{^\circ})}}}$
$\Rightarrow \ \sin{	heta = \sin{75{^\circ}\ \  \Rightarrow \ \ 	heta = 75{^\circ}}}$

Q. If $\sin{\theta = \sin{15{^\circ}}}$+sin 45${^\circ}$ ,where $0{^\circ} < \theta < 90{^\circ}$, then $\theta$ is equal to0

Explanation

Reviewed by Dr. Abubacker

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