Q. $If\ \theta$ is an acute angle and $\tan{\theta = \frac{1}{\sqrt{7}}}$, then the value of $\frac{{cosec}^{2}\theta - \sec^{2}\theta}{{cosec}^{2}\theta + \sec^{2}\theta}$ is

A) 3 /4
B) 1 /2
C) 2
D) 5 /4
Explanation

(a)
Given, $\tan{\theta = \frac{1}{\sqrt{7}}}$
$\therefore\ \frac{cosec^{2} - \sec^{2}\theta}{cosec^{2}\theta + \sec^{2}\theta} = \frac{\left( 1 + \cot^{2}\theta \right) - \left( 1 + \tan^{2}\theta \right)}{\left( 1 + \cot^{2}\theta \right) + \left( 1 + \tan^{2}\theta \right)}$
$= \frac{\left( \cot^{2}{\theta - \tan^{2}\theta} \right)}{2 + \tan^{2}{\theta + \cot^{2}\theta}}$
$= \frac{7 - \frac{1}{7}}{2 + \frac{1}{7} + 7} = \frac{48}{64} = \frac{3}{4}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.